find the perimeter of the rectangle whose length is 40 cm and diagonal is 41 CM
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Let the brradth be b.
√1600+b²=41
40²+b²=41²
b²=41²-40²=(41+40)(41-40)= 81
b=√81=9
Perimeter = 2(40+9) cm= 98 cm
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Answer:
The diagonal of the rectangle divides it into two right-angled triangles, so we can use the pythagorean theorem to solve this problem.
41cm is the diagonal and 40cm is the length.
hyp² = length² + breadth²
41² = 40² + breadth²
1681 = 1600 + breadth²
1681 - 1600 = breadth²
breadth² = 81
breadth = √81
= 9cm
Perimeter = 2( l + b )
= 2 * (40 + 9)
= 2 * 49
= 98cm
The perimeter of the rectangle is 98cm.
Step-by-step explanation:
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