Question

find the perimeter of the rectangle whose length is 40 cm and a diagnal is 41 cm.

Answer 1

formula of rectangle =

2(l+b)=2(40+41)=121

Answer 2

Answer:

Hope it helps............

Step-by-step explanation:

We know that........

A=L√(D^2﹣L^2)

Here,L=Length

,D=Diagonal

,A=Area

Now,According to the question........

Area= Length√(Diagonal^2-Length^2)

=40 √(41^2 - 40^2)

=40 √(1681-1600)

=40 √(81)

=40×9

=360 Cm^2