Question

Find the perimeter of the rectangle whose length is 40 cm and diagonal is 41 cm
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Answer 1

Step-by-step explanation:

2(40+41)=51×2=102 cm

perimeter=102cm

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Answer 2

☞︎︎︎ Given :

• Length of rectangle = 40cm

• Length of diagonal = 41cm

☞︎︎︎ To Find :

• Breadth of rectangle

• Perimeter of rectangle

☞︎︎︎ Solution :

★ We see , if we cut the rectangle from its diagonal then 2 equal right angled triangles will be formed .

∴ Use , Pythagoras Theorem :

✰ H² = B² + P²

☕︎ Here -

• H = 41cm

• B = 40cm

• P = To Find

➪ 41² = 40² + P²

➪ 1681 = 1600 + P²

☆ On Transposing The Terms :

➪ 1681 - 1600 = P²

➪ 81 = P²

★ square from P² will be transposed and square will become square root.

➪ $\sqrt{81}$ = P

∴ P = 9cm (breadth)

☕︎ Now finding Perimeter:

✰ Perimeter = 2( l + b)

★ Here ,

• Length = 40cm

• Breadth = 9cm

➪ Perimeter = 2( 40cm + 9cm )

➪ Perimeter = 2(49cm)

《 ∴ Perimeter = 98cm 》