Math, asked by choyalsamixa, 6 months ago

Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.

Answers

Answered by aagamjn13
0

Answer:

using pythagorus theorem we found that bredth = 9 cm

hence perimeter = 98 cm

Answered by srinivaspasula64
0

Answer:

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Step-by-step explanation:

As we can see in the rectangle, 

By Pythagoras theorem,

Now as given in the question,

Diagonal = 41 cm.

Length = 40 cm.

So, Putting these value we get,

Hence the width of the rectangle is 9 cm.

So 

The perimeter of the rectangle = 2 ( Length + Width )

                                                 = 2 ( 40 cm + 9 cm )

                                                 = 2 x 49 cm

                                                 = 98 cm 

Hence the perimeter of the rectangle is 98 cm.

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