Question

find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm

Answer 1

Perimeter of the rectangle= 2(L+B)
=2(40+B)
Now, we find B

$\sqrt{ l - d} =$
1600_1681=81
81=9
B=9cm
= 2(l+b)
=2(40+9)
P =2*49=98cm
Therefore, perimeter of the rectangle is 98cm

Answer 2

Answer:

98 cm

Step-by-step explanation:

By Pythagoras theorem,

D^2 = L^2 + B^2

=> B^2 = D^2 + L^2

= (41)^2 - (40)^2

= 81

=> B = 9 cms

Now,

Perimeter = 2(L+B)

= 2(40+9)

= 2(49)

= 98 cms

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