Question

find the perimeter of the rectangle whose length is 40 cm and the diagonal is 41cm

Answer 1

Hey mate
Here is ur answer

According to the pythagoras theorem :

A square + b square =c square

40cm 2 + b square = 41cm 2

1600 + b square = 1681cm

B square = 1681 - 1600
= 81

B = 9

Length of the rectangle = 40cm

Breadth of the rectangle = 9cm

Perimeter = 2*(l+b)
= 2* 49
= 98cm square

Perimeter of the rectangle is 98cm square

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Answer 2

Hey mate, here is your answer

In the above figure ABCD is a rectangle with length AB and CD 40cm and Breadth AC and BD 9 cm

To find the area of rectangle we need to find the breadth of rectangle.

In triangle ABC
Base= 40cm,
Hypotenuse=41cm
Perpendicular=?

So, by Pythagoras theorem
H^2=P^2+B^2
(41)^2=P^2+(40)^2
1681=P^2+1600
1681-1600=P^2
√81=P
P=9

Hence breadth of rectangle is 9 cm

Then using the formula find the perimeter of rectangle

Perimeter of rectangle=2(L+B)
=2×(40cm+9cm)
=98 cm

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