Math, asked by coolvani99, 1 year ago

find the perimeter of the rectangle whose length is 40 cm and the diagonal is 41cm

Answers

Answered by dhruvGHDY8
20
Hey mate
Here is ur answer

According to the pythagoras theorem :

A square + b square =c square

40cm 2 + b square = 41cm 2

1600 + b square = 1681cm

B square = 1681 - 1600
= 81

B = 9

Length of the rectangle = 40cm

Breadth of the rectangle = 9cm

Perimeter = 2*(l+b)
= 2* 49
= 98cm square

Perimeter of the rectangle is 98cm square

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Answered by Dotcomputer
5
Hey mate, here is your answer

In the above figure ABCD is a rectangle with length AB and CD 40cm and Breadth AC and BD 9 cm

To find the area of rectangle we need to find the breadth of rectangle.

In triangle ABC
Base= 40cm,
Hypotenuse=41cm
Perpendicular=?

So, by Pythagoras theorem
H^2=P^2+B^2
(41)^2=P^2+(40)^2
1681=P^2+1600
1681-1600=P^2
√81=P
P=9

Hence breadth of rectangle is 9 cm

Then using the formula find the perimeter of rectangle

Perimeter of rectangle=2(L+B)
=2×(40cm+9cm)
=98 cm

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