find the perimeter of the rectangle whose length is 40 cm and the diagonal is 41cm
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Answered by
20
Hey mate
Here is ur answer
According to the pythagoras theorem :
A square + b square =c square
40cm 2 + b square = 41cm 2
1600 + b square = 1681cm
B square = 1681 - 1600
= 81
B = 9
Length of the rectangle = 40cm
Breadth of the rectangle = 9cm
Perimeter = 2*(l+b)
= 2* 49
= 98cm square
Perimeter of the rectangle is 98cm square
Hope U mark brainliest and follow me
Here is ur answer
According to the pythagoras theorem :
A square + b square =c square
40cm 2 + b square = 41cm 2
1600 + b square = 1681cm
B square = 1681 - 1600
= 81
B = 9
Length of the rectangle = 40cm
Breadth of the rectangle = 9cm
Perimeter = 2*(l+b)
= 2* 49
= 98cm square
Perimeter of the rectangle is 98cm square
Hope U mark brainliest and follow me
dhruvGHDY8:
thx
Answered by
5
Hey mate, here is your answer
In the above figure ABCD is a rectangle with length AB and CD 40cm and Breadth AC and BD 9 cm
To find the area of rectangle we need to find the breadth of rectangle.
In triangle ABC
Base= 40cm,
Hypotenuse=41cm
Perpendicular=?
So, by Pythagoras theorem
H^2=P^2+B^2
(41)^2=P^2+(40)^2
1681=P^2+1600
1681-1600=P^2
√81=P
P=9
Hence breadth of rectangle is 9 cm
Then using the formula find the perimeter of rectangle
Perimeter of rectangle=2(L+B)
=2×(40cm+9cm)
=98 cm
✌️I HOPE IT HELPS. PLEASE MARK AS BRAINLIEST✌️
In the above figure ABCD is a rectangle with length AB and CD 40cm and Breadth AC and BD 9 cm
To find the area of rectangle we need to find the breadth of rectangle.
In triangle ABC
Base= 40cm,
Hypotenuse=41cm
Perpendicular=?
So, by Pythagoras theorem
H^2=P^2+B^2
(41)^2=P^2+(40)^2
1681=P^2+1600
1681-1600=P^2
√81=P
P=9
Hence breadth of rectangle is 9 cm
Then using the formula find the perimeter of rectangle
Perimeter of rectangle=2(L+B)
=2×(40cm+9cm)
=98 cm
✌️I HOPE IT HELPS. PLEASE MARK AS BRAINLIEST✌️
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