find the perimeter of the rectangle whose length is 40 cm and diagonal is 41 CM
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answer is 40+40 + 2( (41^2-40^2)^1/2)
= 80 +2×9=98
= 80 +2×9=98
sureandcureheapdtkq9:
your answer is very complicated
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Refer to the attachment above. ⬆️
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