Question

Find the perimeter of the rectangle whose length is 40 cm. and length of one diagonal is 41 cm.

Answer 1

By using pythagoras therom
b²=h²-p² 41²-40²
1681-1600=81 in root
so root of 81 is 9 cm.
so perimeter of rectangle
2(l+b)=2(40+9)
2×49=98cm.Answer .
Hope you help ..............

Answer 2

Answer:

Refer to the attachment above. ⬆️

hope it helps!!