Question

find the perimeter of the rectangle whose length is 40 cm and diagonal is 41 CM

Answer 1

$<b><i>$ Hlw..
Here is the solution... :-)

Length of the rectangle = 40cm

And it's diagonal measures = 41cm

So,

We have to find out it's bredth for the perimeter.

(41)^2 = (40)^2 + (x) ^2

1681 = 1600 + x sq

1681 - 1600 = x^2

81 =x^2

9 = x

Now,

Perimeter of rectangle = 2(l +b)

==> 2 (40 + 9)

==> 2×49

==>98cm

Answer 2

Answer:

98sq cm

Step-by-step explanation:

Length = 40cm

Breadth/ Width=?

Diagnol = 41

By pytagorus theorem:

H^2=O^2+A^2

O^2-H^2-A^2

O^2=41^2-40^2

O^2=1681-1600

O^2=81

O=√ 81

O=9

Perimeter of a rectangle = 2(l+b)

=2(40+9)

=2(49)

=98 sq cm

Hope u got ur answer