Question

Find the perimeter of the rectangle whose length is.40 cm and.Diagonal is 41cm

Answer 1

length = 40cm

diagonal = 41cm

perimeter = 2 multiplied by (length + diagonal)

= 2 multiplied by 81

=162cm

Answer 2

length =41

diagonal =40

breadth =

$\sqrt{ {41 }^{2} - {40 }^{2} } = \sqrt{1681 - 1600} = \sqrt{81}$

$= 9$

perimeter = 2(l+b)=2(40+9)=2(49)=98