Question

find the perimeter of the rectangle whose length is 40 m and a diagonal is 41 m​

Answer 1

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Solution :

D - Diagonal

L - Length

B - Breadth

P - Perimeter

=>D² = L² + B²

=>41² =40² + B²

=>D² = 41²– 40²

=> (41+42) (41–40)

=>81×1

=>81

=>B=\sqrt{81}

=>9

Perimeter => 2 ( l + b )

=> 2(40+9)

=> 98 cm

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Answer 2

$\huge\frak\red{AnSwer}$

D - Diagonal

L - Length

B - Breadth

P - Perimeter

D² = L² + B²

41² =40² + B²

D² = 41²– 40²

= (41+42) (41–40)

=81×1

=81

B=\sqrt{81}

=9

Perimeter => 2 ( l + b )

= 2(40+9)

= 98 cm

Mr.Dexterious⚡