Question

find the perimeter of the rectangle whose length is 40cm and a diagonal is 41 cm

Answer 1

Answer

here, length=40(perpendicular)

hypo=41

acc to pythagorous theorem,

h²=p²+b²

41²=40²+b²

here,

b²=81

b=9

but,

perimeter=2(l+b)

perimeter=2(40+9)

perimeter=98

Step-by-step explanation:

Answer 2

Answer:

98cm

Step-by-step explanation:

As the vertex angle of a rectangle forms 90°

diagonal = Hypotenuse

length = base

breadth = perpendicular

By, Pythagorous theorem

H² = P² + B²

41² = P² + 40²

P² = 41² - 40²

P² = 1681 - 1600

P² = 81

P =√81 = 9cm

breadth = 9cm ; length = 40cm

$\bold{\underline{\underline{Formula}}}$

Perimeter = 2(l + b)

= 2(40 + 9)

= 2(49)

Perimeter = $\large{\boxed{98\:cm}}$

_________________________________

Mark Brainliest, if it helps :)