Question

Find the perimeter of the rectangle whose length is 40cm and diagonal is 41cm.

Answer 1

hell.. ooo!!


>>>by Pythagoras theorem

41^2=40^"+x^2
1681= 1600 + x^2
x^2= 1681-1600=81

x=81 cm
So the breadth is 81 cm
Perimeter= 2(l+b)= 2(40+9)= 2*49= 98 cm

Answer 2

Hello Friend !


The diagonal of a rectangle divides it into two right-angled triangles, so we can use the Pythagorean theorem to solve this problem. Lte us take s as the breadth of the rectangle and the length is already one of the arms of the triangle.

41^2=40^"+x^2

1681= 1600 + x^2

x^2= 1681-1600=81

Therefore, x=81 cm

So the breadth is 81 cm, but since you didn't specify what we have to do in the problem, I'll also the give the perimeter and area.

Perimeter= 2(l+b)= 2(40+9)= 2*49= 98 cm

Area= l*b= 40 * 9= 360 cm^2


Hope this helps !!