Question

Find the perimeter of the rectangle whose length is 40cm and a diagonal is 41 cm​

Answer 1

Answer:

here is your answer mate.......

Step-by-step explanation:

let ABCD be rectangle.

Then AC will be diagonal. And angle B = 90.

Length(BC) = 40 cm

diagonal(AB) = 41 cm

By using pythagoras theorem, we have:-

AB^{2} + BC^{2} = AC^{2}AB2+BC2=AC2

x^{2} + 40^{2} = 41^{2}x2+402=412

AB^{2} = 41^{2} - 40^{2}AB2=412−402

AB^{2} = 1681 - 1600 = 81AB2=1681−1600=81

AB = \sqrt{81} = 9 cmAB=81=9cm

Now, Perimeter of rectangle = 2(L+B) = 2(BC+ AB)

                                         = 2(9 + 40) = 2(49)

                                         = 98 cm

HOPE THAT THIS WILL HELP YOU.....