Question

Find the perimeter of the rectangle whose length is 40cm and a diagonal is 41cm. Explain it too.​

Answer 1

Answer:

98cm

Step-by-step explanation:

P=2(l+w)

d=w2+l2

Solving forP

P=2l+2d2﹣l2=2·40+2·412﹣402=98cm

Answer 2

Answer:

Given,

that length of the side of the rectangle is l=40cm and the length of the diagonal is d=41cm

let breadth be bcm

Therefore, l²+b2² =d²

-> 40²+b²=41²

->b²=81

-> b=9cm

we know that the perimeter of the rectangle is

2(l+b)=2(40+9)=98cm