Find the perimeter of the rectangle whose length is 40cm and a diagonal is 41cm.
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Answered by
11
41cm is the diagonal and 40cm is the length.
hyp² = length² + breadth²
41² = 40² + breadth²
1681 = 1600 + breadth²
1681 - 1600 = breadth²
breadth² = 81
breadth = √81
= 9cm
Perimeter = 2( l + b )
= 2 * (40 + 9)
= 2 * 49
= 98cm
hyp² = length² + breadth²
41² = 40² + breadth²
1681 = 1600 + breadth²
1681 - 1600 = breadth²
breadth² = 81
breadth = √81
= 9cm
Perimeter = 2( l + b )
= 2 * (40 + 9)
= 2 * 49
= 98cm
Answered by
3
HOPE IT MIGHT HELP YOU
______________________________
first we have to find the base breadth
using Pythagorean theorem
40squared+breadth squared=41 squared
after this you will get the breadth
then apply breadth and length in this formula
perimeter of rectangle=2(l+b)
_________________________________
PLEASE MARK AS BRAINLIST AND FOLLOW PLEASE PLEASE
______________________________
first we have to find the base breadth
using Pythagorean theorem
40squared+breadth squared=41 squared
after this you will get the breadth
then apply breadth and length in this formula
perimeter of rectangle=2(l+b)
_________________________________
PLEASE MARK AS BRAINLIST AND FOLLOW PLEASE PLEASE
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