Question

Find the perimeter of the rectangle whose length is 60 cm and diognal is 61 cm

Answer 1

Pic have the solution

Answer 2

------------------HEY DEAR----------------------

HERE IS YOUR ANSWER...............

WE KNOW,

IN CASE OF RECTANGLE A DIAGONAL DIVIDE IT INTO TWO TRIANGLES AND BOTH ARE RIGHT ANGLED TRIANGLES...

SO BY APPLYING PYTHAGORUS THEOREM..

(L)^2 + (B)^2 = (DIAGONAL)^2

L = LENGTH

B = BREADTH

SO PUT VALUES...

(B)^2 = (61)^2 - (60)^2

(B)^2 = 3721 - 3600

(B)^2 = 121

(B) = 11 cm.

SO,  PERIMETER OF RECTANGLE  = 2 (L+B)

                                                             = 2(11 +60)

                                                             = 2(71)

                                                             = 142 cm.

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HOPE IT HELPS YOU...

THANKS...

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