find the perimeter of the rectangle whose length is 7.5cm and diagonal is 8.5cm
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Answered by
34
perimeter of a recatngle =2(l+b)
l=7.5,diagonal=8.5
letthe other side be b
by pythagoras theorem
l^2 + b^2 = diagonal^2
56.25+ b^2 = 72.25
b^2= 72.25- 56.25
= 16
b= 4
perimeter = 2(l+b)
2(7.5+4)
= 2*11.5
= 23
l=7.5,diagonal=8.5
letthe other side be b
by pythagoras theorem
l^2 + b^2 = diagonal^2
56.25+ b^2 = 72.25
b^2= 72.25- 56.25
= 16
b= 4
perimeter = 2(l+b)
2(7.5+4)
= 2*11.5
= 23
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