Question

Find the perimeter of the rectangle whose sides are (4x+y) and (4y-x) respectively​

Answer 1

Question :

Find the perimeter of the rectangle whose sides are (4x+y) and (4y-x) respectively

To find :

The perimeter of a rectangle

Given Data :

• Length = (4x + y)

• Breadth = (4y – x)

Formula Used :

$\sf \small Perimeter \: of \: the \: rectangle = 2(Length + Breadth)$

Solution :

$\sf \small Perimeter = 2(L + B)$

$\sf \small \rightarrow2[(4x + y) + (4y - x)]$

$\sf \small \rightarrow2(4x + y+ 4y - x)$

$\sf \small \rightarrow2(3x + 5y)$

$\sf \small \rightarrow6x + 10y$

$\boxed {\sf \small So \: the \: perimeter \: of \: the \: rectangle \: is \green{\: 6x + 10y}}$

More Information :

• The perimeter of a rectangle is the total length of all the sides of the rectangle.

• Hence, we can find the perimeter by adding all four sides of a rectangle.

• Since opposite sides of a rectangle are always equal, we need to find the dimensions of only two sides to find the perimeter of a rectangle.