Find the perimeter of the rectangle with the following sides
2p2q2 – 3pq + 4 and 5 + 7pq – 3p2q2
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perimeter of rectangle : 2 × ( l + b )
= 2 × ( 2p2q2 - 3pq + 4 + 5 + 7pq - 3p2q2)
= 2×( 2p +2q+2-3p+q+4+7p+q-3p+2q+2)
=2×( 2p-3p +7p-3p +2q+q+q+2q+2+4+2)
=2×(3p+6q+7)
=2×3p =6p
2×6q=12q
2×7=14
perimeter of rectangle is = 6p+12q+ 14
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