Question

find the perimeter of the rhombus whose area is 16cm^2 and one of the diagonal is a 12 cm.​

Answer 1

Answer:

24.59cm

Step-by-step explanation:

Here, AC = 16 cm

BD = 15 cm

Now, OA = 16 cm / 2 or 8 cm

And, OB = 12 cm / 2 or 6 cm

As we know that diagonal of rhombus bisect at 90°

H² = B² + P²

AB² = OA² + OB²

AB² = 8² + 6²

AB = √( 64 + 36 )

AB = 10

Now, as all sides of rhombus are equal so

Perimeter = 4( side )

= 4*10 cm = 40 cm

Answer 2

QUESTION :

• find the perimeter of the rhombus whose area is 16cm^2 and one of the diagonal is a 12 cm.

GIVEN :

• rhombus whose area is 16cm^2

• one of the diagonal is a 12 cm.

TO FIND :

• find the perimeter of the rhombus = ?

SOLUTION :

first we have :

• PR = 16 centimetres

• QS = 15 centimetres

then, we will bisect the rhombus :

• Height = base + perimeter

• PQ = OC + O D

• PQ = 8 + 6

• PQ = √ (64 + 36)

• PQ = 10

• rhombus = 4 × side

rhombus = 4 × 10 = 40 cm

perimeter of the rhombus whose area =

40 cm