find the perimeter of the rohmbus in which the lenghts of the two diagonals are 24m and 10m.
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Answered by
2
Answer:
Perimeter of rhombus is 52
Answered by
2
Answer:
Step-by-step explanation:
Given:
⇒Diagonal 1,
⇒24 m.
⇒Diagonal 2,
⇒10 m.
To find:
⇒Perimeter of rhombus.
Solution:
⇒Perimeter of the rhombus is P=2√d1²+d2².
Calculation:
⇒ P=2√24²+10²,
⇒P=2×√576+100,
⇒P=2×√676,
⇒P=2×26,
⇒P=52,
So,the perimeter of rhombus is 52 m.
Hope it helps.
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