Math, asked by michellerboyer, 4 months ago

Find the perimeter of the shape with vertices (2, 3), (5, 3) and (5, 7).

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Answers

Answered by tanushree52
8

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Answered by Dhruv4886
0

The perimeter of the shape is 12 units

Given:  

The vertices of the shape are (2, 3), (5, 3), and (5, 7).

To find:

Find the perimeter of the shape  

Solution:

Formula used:

The distance between two points (x₁, y₁) and (x₂, y₂)

              d = √[(x₂ - x₁)² + (y₂ - y₁)²]

To find the perimeter of the shape find the distance between 2 sets of points as follows

Distance between (2, 3) and (5, 3)

d₁ = √[(5 - 2)² + (3 - 3)²] = √3² = 3  

Distance between (5, 3) and (5, 7)

d₂ = √[(5 - 5)² + (7 - 3)²]  = √[ 4²]  = 4

Distance between (5, 7) and (2, 3)  

d₃ = √[(2 - 5)² + (3 - 7)²] = √3² + 4² = √25 = 5    

Hence, perimeter of the shape = d₁ + d₂ + d₃

= 3 + 4 + 5 = 12 units

Therefore,

The perimeter of the shape is 12 units

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