Find the perimeter of the shape with vertices (2, 3), (5, 3) and (5, 7).
Answers
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The perimeter of the shape is 12 units
Given:
The vertices of the shape are (2, 3), (5, 3), and (5, 7).
To find:
Find the perimeter of the shape
Solution:
Formula used:
The distance between two points (x₁, y₁) and (x₂, y₂)
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
To find the perimeter of the shape find the distance between 2 sets of points as follows
Distance between (2, 3) and (5, 3)
d₁ = √[(5 - 2)² + (3 - 3)²] = √3² = 3
Distance between (5, 3) and (5, 7)
d₂ = √[(5 - 5)² + (7 - 3)²] = √[ 4²] = 4
Distance between (5, 7) and (2, 3)
d₃ = √[(2 - 5)² + (3 - 7)²] = √3² + 4² = √25 = 5
Hence, perimeter of the shape = d₁ + d₂ + d₃
= 3 + 4 + 5 = 12 units
Therefore,
The perimeter of the shape is 12 units
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