Question

find the perimeter of the square whose area is 256 square.

Answer 1

Step-by-step explanation:

Area of square = 256 sq.units

a^2 = 256

a = 16 unit.

Perimeter of square = 4a

= 4 ( 16 )

= 64 units.

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Answer 2

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Find the perimeter of square whose area is 256 unit square.

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Let, the side of square be 'x' units.

as, we know

$\tt \: ar(square) = {(side)}^{2}$

therefore,

$\tt \: {x}^{2} = 256 \\ \\ \boxed{ \tt \: x = 16 \: units}$

Now,

$\tt \: perimeter \: of \: square = 4(side)$

therefore,

Perimeter of square = 4 (16)

Perimeter of square = 64 units.(Ans.)