Question

Find the perimeter of the square whose each side is -7 cm.​

Answer 1

Step-by-step explanation:

Perimeter of square =4 xside

= 4x(-7)= -28 cm

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Answer 2

Correct Question-:

• Find the perimeter of the square whose each side is 7 cm.

AnswEr-:

• $\underline{\boxed{\star{\sf{\blue{ Perimeter_{(Square)}  \: = \: 28 cm }}}}}$

Explanation-:

$\mathrm{Given-:}$

• The side of square is 7 cm.

$\mathrm{To\:Find-:}$

• The perimeter of square.

$\dag{\mathrm{Solution\:of\:Question-:}}$

• $\underbrace{\sf{Understanding \:the\:Concept-:}}$

• We have to find the Perimeter of Square whose each side is 7 cm long .

• For this we need to put the known or given values in Formula of Perimeter of Square-:

As , We know That ,

• $\underline{\boxed{\star{\sf{\red{ Perimeter_{(Square)}  \: = \: 4 \times side }}}}}$

$\mathrm{Here-:}$

• Side or The length of each side of square is 7 cm

Now, Putting known Values in Formula-:

• $\longrightarrow {\mathrm{Perimeter_{Square}= 4 \times 7 }}$

• $\longrightarrow {\mathrm{Perimeter_{Square}= 28 cm }}$

$\mathrm{Hence-:}$

• $\underline{\boxed{\star{\sf{\blue{ Perimeter_{(Square)}  \: = \: 28 cm }}}}}$

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♡》 More To Know-:

• Formulas of area :

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$

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