Find the perimeter of the trapezium in figure to the right. If x=8 and y=6
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Step-by-step explanation:
Perimeter of trapezium = (x+y+1)+(2x+y)+(x+y)+(x-y)
=(8+6+1)+(2×8+6)+(8+6)+(8-6)
= 15+22+14+2
= 53
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Answered by
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perimeter of trapezium =(x+y+1)+(2x+y)+(x+y)+(x-y)
=(8+6+1)+(2×8+6)+(8+6)+8-6)
=15+22+14+2
=53
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