Math, asked by Sirakmatiyas21, 8 months ago

Find the perimeter of the trapezium in figure to the right. If x=8 and y=6

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Answered by Anonymous
8

Step-by-step explanation:

Perimeter of trapezium = (x+y+1)+(2x+y)+(x+y)+(x-y)

=(8+6+1)+(2×8+6)+(8+6)+(8-6)

= 15+22+14+2

= 53

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Answered by Anonymous
7

perimeter of trapezium =(x+y+1)+(2x+y)+(x+y)+(x-y)

=(8+6+1)+(2×8+6)+(8+6)+8-6)

=15+22+14+2

=53

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