Question

Find the perimeter of the trapezium OPQR in which OR is
perpendicular to OP and RQ; OP = 10 cm, RQ = 15 cm and
OR= 12 cm.
​

Answer 1

Answer:

Step-by-step explanation:

To Find : the perimeter of the trapezium OPQR

Given : In which OR is perpendicular to OP and RQ.OP=10cm,RQ=15cm and OR=12cm.

Solution:  

PQ=?

Join RP

from P to RQ extend a perpendicular and form PT

and

RQ-RT=QT

15-10=QT(RT=OP)

QT= 5 cm

in ∆ PTQ as a right angle triangle

PT²+QT²=PQ²

PQ²=12²+5²

PQ =√(144+25)

PQ =√169

PQ = 13 cm

Perimeter of trapezium = sum of all sides

=>OP+RQ+OR+PQ

=>10+15+12+13

=>50 cm