find the perimeter of the trapezium OPQR in which ORis perpendicular to OP and RQ.OP=10cm,RQ=15cm and OR=12cm.
Answers
Answered by
31
To Find : the perimeter of the trapezium OPQR
Given : In which OR is perpendicular to OP and RQ.OP=10cm,RQ=15cm and OR=12cm.
Solution:
PQ=?
Join RP
from P to RQ extend a perpendicular and form PT
and
RQ-RT=QT
15-10=QT(RT=OP)
QT= 5 cm
in ∆ PTQ as a right angle triangle
PT²+QT²=PQ²
PQ²=12²+5²
PQ =√(144+25)
PQ =√169
PQ = 13 cm
Perimeter of trapezium = sum of all sides
=>OP+RQ+OR+PQ
=>10+15+12+13
=>50 cm
Given : In which OR is perpendicular to OP and RQ.OP=10cm,RQ=15cm and OR=12cm.
Solution:
PQ=?
Join RP
from P to RQ extend a perpendicular and form PT
and
RQ-RT=QT
15-10=QT(RT=OP)
QT= 5 cm
in ∆ PTQ as a right angle triangle
PT²+QT²=PQ²
PQ²=12²+5²
PQ =√(144+25)
PQ =√169
PQ = 13 cm
Perimeter of trapezium = sum of all sides
=>OP+RQ+OR+PQ
=>10+15+12+13
=>50 cm
Attachments:
Answered by
5
Answer:
50cm
Step-by-step explanation:
According to question
RQ=15cm
RT=10cm
thus TQ=(15-10)cm=5cm
Using pythagoras
PQ^2=12^2+5^2
PQ^2=144+25
PQ^2=169
PQ=13cm
Perimeter of trapezium=Sum all side
=(12+10+15+13)cm
=50cm
Similar questions