Find the perimeter of the triangle a = 60√3 b= 60 c=120
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Perimeter of triangle=sum of all sides
a=60√3
b=60
c=120
a+b+c=60√3+60+120
a+b+c=180+60√3
a+b+c=60(3+√3)
a+b+c=60√3(√3+1)
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Anonymous:
can u simplify as much as u can
Answered by
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perimeter of triangle (P) = a+ b + c
P =60√3 + 60 + 120
= 180 + 60√3
= 60 ( 3 + √3 )
in mathematics ,in some cases we takes value of √3 = 1.78 but in actual it's 1.73
so now,
= 60(3+1.78)
= 60 ×4.78
= 286.8
hope it helps!
thank you !
P =60√3 + 60 + 120
= 180 + 60√3
= 60 ( 3 + √3 )
in mathematics ,in some cases we takes value of √3 = 1.78 but in actual it's 1.73
so now,
= 60(3+1.78)
= 60 ×4.78
= 286.8
hope it helps!
thank you !
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