Question

find the perimeter of the Triangle formed with vertices (0 4 )(0 0) (3 0)​

Answer 1

Answer:

we Further, adding all the distance of a triangle to get the perimeter of a triangle.We plot the vertices of a triangle i.e., (0, 4), (0,0) and (3,0)  Now,perimeter of ΔAOB=Sum of the length of all its sides = d(AO) + d(OB) + d(AB) ∴ Distance between the points (x ,y ) and (x , y ), Hence, the required perimeter of triangle is 12. 125414/the-perimeter-of-a-triangle-with-vertices-0-4-0-0-and-3-0-is-a-5-b-12-c-11-d-7-5

Answer 2

Answer:

Step-by-step explanation:

Given :-

Vertices are (0 4 ), (0 0) and (3 0)​.

To Find :-

The perimeter of the Triangle.

Formula to be used :-

Distance formula.

Solution :-

Let A( 4 , 0) B(0, 0) and C (0 , 3)

According to the Question

AB =√(4² + 0) = 4

BC = √(0 + 3²) = 3

CA =√(4² + 3²) = 5

Perimeter of Triangle = Sum of all sides

Perimeter of Triangle = 4 + 3 + 5

Perimeter of Triangle = 12 unit

Hence, the perimeter of the Triangle is 12 unit.