Find the perimeter of the triangle formed with vertices (5,0) (4,_2)& (2,_1)
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To find the perimeter of the triangle with vertices (5,0) (4,-2) & (2,-1), we have to first find distance between each pair of points, which will give length of the sides. Hence, if length of sides are L1, L2, L3. These are as follows:
L1 = √(4-5)² + (-2-0)² = √5
L2 = √(2-4)² + (-1+2)² = √5
L3 = √(2-5)² + (-1-0)² = √10
Perimeter is, √5 + √5 + √10 = √20 = 4.47
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