Question

Find the perimeter of the triangle, if the area of an isosceles right triangle is $8cm^{2}$

Answer 1

Answer:

Step-by-step explanation:

area of triangle =8

1×b×h      =8

   2

b×h=16

b²=16                   (isosceles triangle two sides are equal)

b=4

now,

       h=4

now hypotenuse becomes,

4²+4²=4√2

now perimeter = 4+4+4√2

                         =4(1+1+√2)

                         =4(2+√2)cm

pls follow if u like this solution