Question

Find
the
perimeter of the triangle obtained by
joining (3, 1) (6,4) & (8,6)​

Answer 1

The perimeter of the Triangle obtained by joining (3, 1) (6, 4) & (8, 6) is :-

Distance between the coordinates is calculated by :

\sqrt{(x1-x2)^2-(y1-y2)^2

so

L1= \sqrt{(3-8)^2-(1-6)^2 = 5 \sqrt{2}

L2= \sqrt{(3-6)^2-(1-4)^2 = 3 \sqrt{2}

L3= \sqrt{(8-6)^2-(6-4)^2 = 2 \sqrt{2}

Adding L1, L2, L3 will give the perimeter of the triangle.

L1+L2+L3 = 5 \sqrt{2}+ 3 \sqrt{2} +2 \sqrt{2}

Perimeter = 10 \sqrt{2}