Question

Find the perimeter of the triangle obtained by joining(3,1),(6,4)&(8,6)

Answer 1

Perimeter is 10√2 units.

Step-by-step explanation:

The three vertices of the triangle are (3,1), (6,4) and (8,6).

Let, A, B, and C are those vertices respectively.

So, the length of AB = $\sqrt{(6 - 3)^{2} + (4 - 1)^{2}} = 3\sqrt{2}$ units.

Length of BC = $\sqrt{(8 - 6)^{2} + (6 - 4)^{2}} = 2\sqrt{2}$ units.

And the length of AC = $\sqrt{(8 - 3)^{2} + (6 - 1)^{2}} = 5\sqrt{2}$ units.

Therefore, the perimeter of the triangle will be

$(5\sqrt{2} + 2\sqrt{2} + 3\sqrt{2})$ units

= $10\sqrt{2}$ units. (Answer)

Answer 2

Answer:

the perimeter of triangle will be (5√2 + 2√2 + 3√2) units