Question

Find the perimeter of the triangle
when ABC when AB = 11/4m, BC = 20/5m, AC= 63/8m​

Answer 1

Answer:

Step-by-step explanation:

perimeter is sum of sides

so simply adding AB,BC,AC we get perimeter

11/4+20/5+63/8=perimeter

which is 11/4+4+63/8 taking LCM we get

(22+32+63)/8=117/8m

this is the answer

HOPE THIS HELPED YOU

Answer 2

Answer:

Step-by-step explanation:

Hope it helps u mate.

Perimeter of a triangle = sum of all sides

AB = 11/4m

BC = 20/5 = 4m

AC = 63/8

Therefore, 11/4+4/1+63/8

LCM of 4,1 and 8 = 8

= 22/8+32/8+63/8

= 127/8 m