Question

find the perimeter of the triangle whose sides are 12m, 19m, and 28m.​

Answer 1

Answer:

perimeter of triangle = a+b+c

Step-by-step explanation:

therefore, 12+19+28 =

= 59 CM

Answer 2

Given : The sides of Triangles are 12 m , 19 m and 28 m , respectively.

Need To Find : Perimeter of Triangle .

⠀⠀⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

$\bf{\sf{ Solution \:of\:Question \::}}$

⠀⠀⠀⠀⠀⠀⠀⠀We know that if we are given with all three sides [ Side A , Side & Side C ] and we need to find Perimeter of Triangle using the Required formula that is :

⠀⠀⠀⠀⠀ $\implies {\underline {\sf{ Perimeter _{( Triangle)} = Side\:A+Side\:B+Side \:C \:units .}}}$

⠀⠀⠀⠀⠀Here Side A is the First Side of Triangle, Side B is the second side of triangle & Side C is the third side of triangle and we are given with all the sides of Triangle,. So by using the given formula we can find the Perimeter of Triangle :

⠀⠀⠀⠀⠀⠀$\underline {\sf{\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}}$

⠀⠀⠀⠀⠀⠀ $\sf{\longmapsto {Perimeter\:= \:12 +\:19+\:28 }}$

⠀⠀⠀⠀⠀⠀ $\sf{\longmapsto {Perimeter\:= \:\:31+\:28 }}$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm { Perimeter = 59 \: m}}}}$

Therefore,

⠀⠀⠀⠀⠀$\underline {\therefore\:{\pink{ \mathrm { Perimeter \:of\:Triangle \:is\:59\: m}}}}$

⠀⠀⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

$\Large {\boxed {\sf|\:\:{\underline {\bf{ More \:To\:Know }}}\:\:|}}$

• $\longrightarrow {\sf{ Perimeter _{( Triangle)} = Side\:A+Side\:B+Side \:C \:units .}}$

• $\longrightarrow {\sf{ Perimeter _{( Rectangle)} = 2( Length + Breadth)\:units .}}$

• $\longrightarrow {\sf{ Perimeter _{( Square)} = 4 \times Side \:units .}}$

• $\longrightarrow {\sf{ Circumference _{( Circle)} = 2 \times\pi \times Radius \:units .}}$

⠀⠀⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀