Question

find the perimeter of the triangle whose sides are(3x+4y-z)units (x+4y+5z) and (4x-3y+7z)units​

Answer 1

Answer:

perimeter of triangle=sum of all the sides

(3x+4y-z)+(x+4y+5z)+(4x-3y+7z)

=3x+4y-z+x+4y+5z+4x-3y+7z

=3x+x+4x+4y+4y-3y-z+5z+7z

=(8x+5y+11z) units.

Answer 2

Step-by-step explanation:

formula of perimeter of a triangle is side +side+side

=p=(3x+4y-z)+(x+4y+5z)+ (4x-3y+7z)

p=8x+5y+11z (ans)

hope it helped you

thanks......