find the perimeter of the triangle whose sides are ( 3x+4y-z) units(x+4y+5z)unts and (4c-3y+7z)units
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Answer:
4x+5y-11z+4c
Step-by-step explanation:
i don't think it is correct....i tried my best
perimeter of a triangle = sum of the sides
= 3x+4y+-z+x+4y+5z+4c-3y+7z
= 4x+5y-11z+4c
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