Find the perimeter of the triangle whose sides are a + b - 3c, - a - b + 6c and 7a - b + 9c
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Given :
- First side of the triangle = a + b - 3c
- Second side of the triangle = - a - b + 6c
- Third side of the triangle = 7a - b + 9c
To find :
- Perimeter of the triangle
Concept :
Perimeter of any geometric shape is the sum of all its sides.
Mathematically,
- Perimeter of triangle = a + b + c
where,
- a, b and c are the three sides of the triangle
Solution :
Perimeter of the triangle :-
→ Perimeter = a + b + c
Substituting the given values, we get :-
→ Perimeter = a + b - 3c + (- a - b + 6c) + (7a - b + 9c)
→ Removing the brackets and changing the signs.
→ Perimeter = a + b - 3c - a - b + 6c + 7a - b + 9c
→ Perimeter = a - a + 7a + b - b - b - 3c + 6c + 9c
→ Cancelling the variables with the opposite signs.
→ Perimeter = 7a - b - 3c + 6c + 9c
→ Adding the same variables.
→ Perimeter = 7a - b - 3c + 15c
→ Perimeter = 7a - b + 12c
Therefore,
- Perimeter of the triangle whose sides are a + b - 3c, - a - b + 6c and 7a - b + 9c is 7a - b + 12c
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KNOW MORE :
Signs are changed on the following basis :-
- (+) (+) = (+)
- (-) (-) = (+)
- (+) (-) = (-)
- (-) (+) = (-)
Some formulae related to triangles :-
- Semi - perimeter = Perimeter ÷ 2
- Heron's formula = √s(s - a)(s - b)(s - c)
- Area of Isosceles triangle = ½ × b × h
- Area of equilateral triangle = √3/4 a²
where,
- b stands for the base of the triangle
- h stands for the height of the triangle
- a stands for the side of the triangle
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