Find the perimeter of the triangle whose vertices are (0,12), (0,0) and (5,0)
Answers
Answer:
30 cm
Step-by-step explanation:
Answer:
Step-by-step explanation: Let the point be A(0,6),B(0,0),C(5,0)
to find the perimeter of ΔABC
find the length of each side
by using distance formula d=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
AB=
(0−0)
2
+(0−6)
2
=6 unit
BC=
(5−0)
2
+(0−0)
2
=5unit
CA=
(0−5)
2
+(6−0)
2
=
61
unit
Now perimeter of Δ=6+5+
61
=11+
61
unitLet the point be A(0,6),B(0,0),C(5,0)
to find the perimeter of ΔABC
find the length of each side
by using distance formula d=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
AB=
(0−0)
2
+(0−6)
2
=6 unit
BC=
(5−0)
2
+(0−0)
2
=5unit
CA=
(0−5)
2
+(6−0)
2
=
61
unit
Now perimeter of Δ=6+5+
61
=11+
61
unit