Question

find the perimeter of the triangle whose vertices are (-2, 1), (4, 6) &(6, 3)?? ​

Answer 1

Answer:

☆ QUESTION ☆

find the perimeter of the triangle whose vertices are (-2, 1), (4, 6) &(6, 3)??

☆ ANSWER ☆

LET

A = (-2,1)

B =(4,6)

C = (6,3)

PERIMETER OF THE TRIANGLE = SUM OF ALL THE SIDES...

THEREFORE

P = AB + BC + AC

$ab \: = \sqrt{6 {}^{2} + 5 {}^{2}} \\ ab \: = \sqrt{36 + 25 } \\ ab \: = \sqrt{66}$

$bc \: = \sqrt{2 {}^{2} + 3 {}^{2} } \\ bc \: = \sqrt{13}$

$ac \: = \sqrt{8 {}^{2} + 2 {}^{2} } \\ ac \: = \sqrt{64 + 4} \\ ac \: = \sqrt{68}$

AB + BC + AC

=

$\sqrt{66 + 13 + 68 } \\ = \sqrt{147} \: units$

Answer 2

dont know the ans tell u after