find the perimeter of the triangle whose vertices are (3,2) (1,−2) and (−1,2)
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Step-by-step explanation:
Solution:
Let A(3,10),B(5,2) and C(14,12) be the coordinates of the vertices of a triangle.
AB=
(3−5)
2
+(10−2)
2
=
4+64
=
68
=2
17
units =8.25 units
BC=
(14−5)
2
+(12−2)
2
=
81+100
=
181
=13.45 units
AC=
(3−14)
2
+(10−12)
2
=
121+4
=
125
=5
5
units
=11.180 units
So, perimeter of the required triangle =AB+BC+AC
=8.25+13.45+11.180 units
=32.880 units
Video Explanation
Solution To Question ID 610438
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