Math, asked by bobosamath, 16 days ago

find the perimeter of the triangle whose vertices are (3,2) (1,−2) and (−1,2)

Answers

Answered by jaya782732
1

Step-by-step explanation:

Solution:

Let A(3,10),B(5,2) and C(14,12) be the coordinates of the vertices of a triangle.

AB=

(3−5)

2

+(10−2)

2

=

4+64

=

68

=2

17

units =8.25 units

BC=

(14−5)

2

+(12−2)

2

=

81+100

=

181

=13.45 units

AC=

(3−14)

2

+(10−12)

2

=

121+4

=

125

=5

5

units

=11.180 units

So, perimeter of the required triangle =AB+BC+AC

=8.25+13.45+11.180 units

=32.880 units

Video Explanation

Solution To Question ID 610438

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