find the perimeter of the triangle whose vertices are (3, 2), (2, -3) and, (0, 0) is
Answers
Answered by
1
Answer:
root 52 units
Step-by-step explanation:
Distance =root (x2- x1)^2+(y2-y1)^2
AB=root( 2-3)^2+(-3-2)^2
AB=root 1+25
AB = root 26 units
BC=root (0-2)^2+(0+3)^2
BC=root 4+9
BC= root 13units
AC =root (0-3)^2+(0-2)^2
AC=root 9+4
AC=root 13 units
THEN,
perimeter=AB+BC+AC
=root 26+root 13+ root 13
=root 26+root 26
=root 52units
Similar questions
Math,
5 months ago
English,
5 months ago
Political Science,
11 months ago
Social Sciences,
11 months ago
Physics,
1 year ago