Math, asked by subramanyamreddyvart, 11 months ago

find the perimeter of the triangle whose vertices are (3, 2), (2, -3) and, (0, 0) is​

Answers

Answered by bhagyalakshmicements
1

Answer:

root 52 units

Step-by-step explanation:

Distance =root (x2- x1)^2+(y2-y1)^2

              AB=root( 2-3)^2+(-3-2)^2

              AB=root 1+25

             AB = root 26 units

             BC=root (0-2)^2+(0+3)^2

             BC=root 4+9

             BC= root 13units

              AC =root (0-3)^2+(0-2)^2

             AC=root 9+4

              AC=root 13 units

THEN,

perimeter=AB+BC+AC

                =root 26+root 13+ root 13

                =root 26+root 26

               =root 52units

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