Question

find the perimeter of the triangle whose vertices are (root 2,root3),(-root 2,-root 3) and (0,2)​

Answer 1

Answer:

Hey mate plzz refer to the attachment

Answer 2

Answer:

√20 + √(9 - 4√3)  + √(9 + 4√3)

Step-by-step explanation:

find the perimeter of the triangle whose vertices are (root 2,root3),(-root 2,-root 3) and (0,2)​

A = (√2 , √3)

B = (-√2 , -√3)

C= (0,2)

AB = √ (√2 - (-√2))² + (√3 - (-√3))² = √8 + 12 = √20

AC = √ (√2 - 0)² + (√3 - 2)² = √2 + 3 + 4 - 4√3 = √(9 - 4√3)

BC = √ (-√2 - 0)² + (-√3 - 2)² = √2 + 3 + 4 + 4√3 = √(9 + 4√3)

Perimeter = AB+ BC + AC

= √20 + √(9 - 4√3)  + √(9 + 4√3)