Question

Find the perimeter of the triangle whose vertices are the points (3, 1, 5), (- 1,- 1,9) and (0, - 5, 1).

Answer 1

Answer:

22.81

Step-by-step explanation:

AB=(1−,1−,9)−(3,1,5)=(−4,−2,4)∣AB∣=42+22+42=6BC=(3,1,5)−(0,−5,1)=(3,6,4)∣BC∣=9+36+16=61CA=(0,−5,1)−(−1,−1,9)=(1,−4,−8)∣CA∣=12+42+82=64+16+1=9

Perimeter=∣AB∣+∣BC∣+∣CA∣

=6+61+9=15+7.81=22.81