Find the perimeter of the triangle whose vertices are the points (3, 1, 5), (- 1,- 1,9) and (0, - 5, 1).
Answers
Answered by
1
Answer:
22.81
Step-by-step explanation:
AB=(1−,1−,9)−(3,1,5)=(−4,−2,4)∣AB∣=42+22+42=6BC=(3,1,5)−(0,−5,1)=(3,6,4)∣BC∣=9+36+16=61CA=(0,−5,1)−(−1,−1,9)=(1,−4,−8)∣CA∣=12+42+82=64+16+1=9
Perimeter=∣AB∣+∣BC∣+∣CA∣
=6+61+9=15+7.81=22.81
Attachments:
Similar questions