Question

Find the perimeter of this figure :- ​

Answer 1

$\Large{\underbrace{\sf{\orange{Required\:Solution:}}}}$

We know thαt,

★$\large{\boxed{\sf{\orange{ Perimeter_{(circle)} = 2 \pi r}}}}$

• Substitute the values and take radius = 3m

$\implies{\sf{2 \times \dfrac{22}{7} \times 3}}$

$\implies{\sf{ \dfrac{132}{7}}}$

$\large\implies{\boxed{\sf{ 18.85}}}$

Perimeter of the Semicircle = $\displaystyle{\sf{ \dfrac{1}{2} \times 18.85}}$

$\large\implies{\boxed{\sf{ 9.42}}}$

Now, 9.42 + 12m + 6m + 12m

$\implies{\sf{9.42 + 12m + 6m + 12m }}$

$\large{\boxed{\sf{\orange{39.42m}}}}$

Hence, the perimeter is 39.42m.

And we are done! :D

__________________________

Answer 2

$\large \red{\textsf{Given : A figure}}$

→ The dimensions of the rectangle in the figure are, Length = 12 m, Breadth = 6 m.

→ The Semi Circle has diameter of 6m,

So, the radius will be

$\implies \rm \frac{d}{2} \\ \\ \rm \implies \frac{6}{2} \\ \\ \implies \rm \bf 3m$

$\large \red{\textsf{To find :}}$

• The perimeter of the figure.

Perimeter of the outer three sides of the rectangle

→ 12 m + 6 m + 12 m

$\implies \rm \bf \red{30 m}$

As we know that,

$\large{\red{\textsf{Perimeter of Circle = 2 \pi r }}}$

So, Perimeter of outer arc of the semi circle = 2πr/2 = πr

→ 22/7 × 3

$\implies \rm \bf \red{9.42 m}$

Therefore,

Total Perimeter of the given figure,

→ 30 m + 9.42 m

$\implies \rm \bf \blue{39.42 m}$

Hence, the perimeter of the given figure is 39.42 meter.