Question

find the perimeter of triangke whose sides are 3/5 and 3 1/2 and 3 1/2

Answer 1

Answer:

$\frac{76}{10}$

OR

7.6

Step-by-step explanation:

To find your answer you have to do this,

$\frac{3}{5} + 3 \frac{1}{2} + 3 \frac{1}{2}$

$= \frac{3}{5} + \frac{7}{2} + \frac{7}{2}$

As formula for perimeter of triangle is sum of all sides,

$= \frac{6 + 35 + 35}{10}$

$= \frac{76}{10} \: or \: 7.6$

which is your answer....

....

Hope this will help you and please mark me as brainliest

Answer 2

Answer:

we know that the perimeter of triangle be a+b+c=2s .

where a,b and c side of a triangle

here,given that sides of triangle are 3/5,3 1/2 and 3 1/2

now putting the value of sides in above equation

3/5+3 1/2 +3 1/2= 2s

3/5+ 7/2+7/2=2s

LCM of 5,2,2= 10

now

6+35+35/10=2s

76/10=2s

perimeter of a triangle = 76/10