Find the perimeter of triangle
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Answer:
21 is a perimeter of a triangle please mark me Branlyist
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Question :
Find the perimeter of triangle whose dimensions are :
- AB = 9 units
- BC = 7 units
- AC = 10/2 units
Required Answer :
The perimeter of triangle = 21 units
Given :
We are given the dimensions of a triangle :-
- AB = 9 units
- BC = 7 units
- AC = 10/2 units
To find :
- The perimeter of the triangle
Solution :
Perimeter is the sum of all sides.
Formula to calculate the perimeter of triangle :
- Perimeter = a + b + c
where,
- a denotes the first side
- b denotes the second side
- c denotes the third side
Substituting the given values :
⇒ Perimeter of triangle = 9 + 7 + 10/2
⇒ Perimeter of triangle = 9 + 7 + 5
⇒ Perimeter of triangle = 21
Therefore,
- The perimeter of triangle = 21 units
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Knowledge Bytes :
- Area of isosceles triangle = ½ × b × h
- Semi perimeter = Perimeter ÷ 2
- Heron's formula = √s(s - a)(s - b)(s - c)
- Area of equilareral triangle = √3/4 a
where,
- s denotes the semi perimeter
- a denotes the side of the triangle
- b denotes the base
- h denotes the height
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