Question

find the perimeter of triangle ABC, if the perimeter of triangle ABD is 30 cm and BC-AD =2 cm .pls answer frds ​

Answer 1

Answer:

perimeter of triangle ABD=AB+BD+DA

30 = 13+5+DA

30-18=AD

AD=12cm

BC-AD=2

BC-12=2

BC=14cm

AD =12 so angle ADC=90°

AC^2=AD^2+DC^2

AC^2= 12^2+ (BC-BD)^2

AC^2 =144+(14-5)^2

AC^2 =144+81

AC^2 =225

AC. = 15cm

perimeter of triangle ABC=AB+BC+CA

=13+14+15

= 42cm answer

Answer 2

Answer:

Correct option is C)

Ratio of areas of similar triangle =(sides)

2

arΔDEF

arΔABC

=

81

144

Let the Largest of the triangle DEF=x

(

x

36

)

2

=

81

144

⇒

x

36

=

81

144

⇒

x

36

=

9

12

⇒x=

12

36×9

⇒

x=27cm

Option C