find the perimeter of triangle abc whose sides are 23/5 22/7 and16/3
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Answer:
perimeter of a triangle = sum of all 3 sides
Step-by-step explanation:
sides = 23/5 + 22/7 + 16/3
L.C.M of 5 ,7,3 = 3 * 5* 7 = 105
23/5 = 483/105
22/7 = 330/105
16/3 = 560/105
now, add 483/105 , 330/105 , 560/105
= 1373/105
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